Which values of p and q result in an equation with exactly one solution? 2x+q=px−31 choose all answers that apply: choose all answers that apply: a -q=−31 and p=−2 b- q=31 andp=2 c - q=−31 and p=2 d - q=-2q=−2 and p=2

Option A is correct

Values of P = -2 and Q = -31

Step-by-step explanation:

Given the equation:

Now, we put the given values

A.

Q = -31 and P = -2

2x + (-31) = -2x - 31

2x - 31 = -2x -31  

4x = -31 + 31

4x = 0

x = 0    [one solution]

B.

Q = 31 and P = 2

2x + Q = Px -31

2x + 31 = 2x -31

Subtract 2x from both sides we get

31 = -31        False.

C.

Q = -31 and P = 2

2x + (-31) = 2x - 31

2x - 31 = 2x - 31     [More than one solutions, for any x]

D.

Q = -2 and P = 2

2x + Q = Px -31

2x + (-2) = 2x -31

2x -2 = 2x -31

2x - 2x = -31 + 2      

Combine like term;

0 = -29       False.

Therefore, the values of P and Q results in an equation with exactly one solution is; P = -2 and Q = -31

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign