If f(x)=x^2-x and g(x)=x+1, determine f (g(x)) in simplest from

f(g(x)) = x^2 +x

Step-by-step explanation:

To find f(g)(x) , we substitute g(x) in for x in the function f(x)

f(x) = x^2 -x

f(g(x)) = g(x)^2 -g(x)

          = (x+1)^2 - (x+1)

           = (x+1)*(x+1) - (x+1)

FOIL the square

             (x+1) (x+1)

         First x*x = x^2

        outer x*1 = x

        inner 1*x = x

       last  1*1 =1

Add them together

x^2 + x+x+1 = x^2+2x+1

f(g(x)) = (x+1)*(x+1) - (x+1)

           = x^2+2x+1 -(x+1)

Distribute the -1

          = x^2 +2x+1 -x-1

          = x^2 +x

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12