Solve for x (3x-+3)-0 smaller x=? larger x=?

x=2  and x=3

Step-by-step explanation:

(3x-6)(-x+3)=0

We can use the zero product property to solve for x

3x-6 = 0 and -x+3 =0

3x-6 = 0

Add 6 to each side

3x-6+6 = 6

3x=6

Divide by 3

3x/3 =6/3

x =2

-x+3 =0

Add x to each side

-x+x+3 = +x

3 =x

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

answer: ask

step-by-step explanation: