Father is four times older than his son. in 14 years the father will be twice as old. what are their current ages?

The son is 7 years old

The father is 28 years old

Step-by-step explanation:

f = fathers age

s = sons age

f = 4s

In 14 years  ( so we add 14 to the age)

f+14 = 2(s+14)

We have 2 equations and 2 unknowns

Replace every f with 4s  (from the first equation)

4s+14 =2(s+14)

Distribute the 2

4s+14 = 2s+28

Subtract 2s from each side

4s-2s+14 = 2s-2s+28

2s+14 = 28

Subtract 14 from each side

2s-14-14 = 28-14

2s = 14

Divide by 2

2s/2 =14/2

s =7

The son is 7 years old

Now lets calculate the fathers age

f =4s

f =4*7

f = 28

The father is 28 years old

the answer is 175.4379

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.