An artist designed a badge for a school club. figure abcd on the coordinate grid below shows the shape of the badge: a trapezoid abcd drawn on a 4−quadrant coordinate grid with vertices a(−8, 5), b(−5, 5), c(−6, 7) and d(−7, 7). point j located at (−6, −8) and point m located at (−3, −2) the badge is enlarged and plotted on the coordinate grid as figure jklm with point j located at (−6, −8) and point m located at (−3, −2). which of these could be the coordinates for point l? (−3, −8) (−1, −2) (2, −8) (0, −2)

D- (0,2)

Step-by-step explanation:

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step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240