Write an equation of the line that passes through (1,2) and is parallel to the line y=−5x+4

y=-5x+6

Step-by-step explanation:

For the equation y=-5x+4, the slope is -5 and the slope of the new line will be the same because it is parallel to this line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-2)=-5(x-1)

y-1=-5x+5

y=-5x+6

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐