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Mathematics, 25.06.2019 18:00 lesli4115
Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.a f(x) = −1/2 (x − 6)2 + 3/2b f(x) = 1/2 (x − 6)2 + 3/2c f(x) = −1/2 (x + 3/2)2 + 6d f(x) = 1/2 (x + 3/2)2 + 6 make sure to provide how you got the answer, i want to know how to do these for future reference. also, make sure to incorporate the distance formula methodd=![\sqrt{(x_{2} -x_{1})^{2} + (y_{2}-y_{1})^{2} }](/tex.php?f=\sqrt{(x_{2} -x_{1})^{2} + (y_{2}-y_{1})^{2} })
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Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.a f(x) = −1/2 (x...
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