Mathematics, 22.09.2019 09:00 mbol7123

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Asap 30 + brainliest only solve 2 - 5

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Answer from: collegebound3506

QUESTION 2a

We want to find the area of the given right angle triangle.

We use the formula

$Area=\frac{1}{2}\times base\times height$

The height of the triangle is =a cm .

The base is 12cm .

We substitute the given values to obtain,

$Area=\frac{1}{2}\times 12\times a cm^2$ .

This simplifies to get an expression for the area to be

Area=6a cm^2 .

QUESTION 2b

The given diagram is a rectangle.

The area of a rectangle is given by the formula

$Area=length \times width$

The length of the rectangle is l=7cm and the width of the rectangle is w=ycm .

We substitute the values to obtain the area to be

$Area=7 \times y$

The expression for the area is

Area=7y

QUESTION 2c.

The given diagram is a rectangle.

The area of a rectangle is given by the formula

$Area=length \times width$

The length of the rectangle is l=2x cm and the width of the rectangle is w=4 cm .

We substitute the values to obtain the area to be

$Area=2x \times 4$

The expression for the area is

Area=8x

QUESTION 2d

The given diagram is a square.

The area of a square is given by,

Area=l^2 .

where l=b m is the length of one side.

The expression for the area is

Area=b^2 m^2

QUESTION 2e

The given diagram is an isosceles triangle.

The area of this triangle can be found using the formula,

$Area=\frac{1}{2}\times base\times height$ .

The height of the triangle is 4cm .

The base of the triangle is 6a cm .

The expression for the area is

$Area=\frac{1}{2}\times 6a \times 4cm^2$

Area=12a cm^2

QUESTION 3a

Perimeter is the distance around the figure.

Let P be the perimeter, then

P=x+x+x+x

The expression for the perimeter is

P=4x mm

QUESTION 3b

The given figure is a rectangle.

Let P, be the perimeter of the given figure.

P=L+B+L+B

This simplifies to

P=2L+2B

P=2(L+B)

QUESTION 3c

The given figure is a parallelogram.

Perimeter is the distance around the parallelogram

Perimeter=3q+P+3q+P

This simplifies to,

Perimeter=6q+2P

Perimeter=2(3q+P)

QUESTION 3d

The given figure is a rhombus.

The perimeter is the distance around the whole figure.

Let P be the perimeter. Then

P=5b+5b+5b+5b

This simplifies to,

P=20b mm

QUESTION 3e

The given figure is an equilateral triangle.

The perimeter is the distance around this triangle.

Let P be the perimeter, then,

P=2x+2x+2x

We simplify to get,

P=6x mm

QUESTION 3f

The figure is an isosceles triangle so two sides are equal.

We add all the distance around the triangle to find the perimeter.

This implies that,

Perimeter=3m+5m+5m

Perimeter=13m mm

QUESTION 3g

The given figure is a scalene triangle.

The perimeter is the distance around the given triangle.

Let P be the perimeter. Then

P=(3x+1)+(2x-1)+(4x+5)

This simplifies to give us,

P=3x+2x+4x+5-1+1

P=9x+5

QUESTION 3h

The given figure is a trapezium.

The perimeter is the distance around the whole trapezium.

Let P be the perimeter.

Then,

P=m+(n-1)+(2m-3)+(n+3)

We group like terms to get,

P=m+2m+n+n-3+3-1

We simplify to get,

P=3m+2n-1 mm

QUESTION 3i

The figure is an isosceles triangle.

We add all the distance around the figure to obtain the perimeter.

Let be the perimeter.

Then P=(2a-b)+(a+2b)+(a+2b)

We regroup the terms to get,

P=2a+a+a-b+2b+2b

This will simplify to give us the expression for the perimeter to be

P=4a+3b mm.

QUESTION 4a

The given figure is a square.

The area of a square is given by the formula;

Area=l^2

where l=2m is the length of one side of the square.

We substitute this value to obtain;

Area=(2m)^2

This simplifies to give the expression of the area to be,

Area=4m^2

QUESTION 4b

The given figure is a rectangle.

The formula for finding the area of a rectangle is

$Area=l\times w$ .

where l=5a cm is the length of the rectangle and w=6cm is the width of the rectangle.

We substitute the values into the formula to get,

$Area =5a \times 6$

Area =30a cm^2

QUESTION 4c

The given figure is a rectangle.

The formula for finding the area of a rectangle is

$Area=l\times w$ .

where l=7y cm is the length of the rectangle and w=2x cm is the width of the rectangle.

We substitute the values into the formula to get,

$Area =7y \times 2x$

The expression for the area is

Area =14xy cm^2

QUESTION 4d

The given figure is a rectangle.

The formula for finding the area of a rectangle is

$Area=l\times w$ .

where l=3p cm is the length of the rectangle and w=p cm is the width of the rectangle.

We substitute the values into the formula to get,

$Area =3p \times p$

The expression for the area is

Area =3p^2 cm^2

See attachment for the continuation

Answer from: Quest

Ineed show the photo because i need more information

Answer from: Quest

Hello!

the answer is:

the correct option:

b. $x=2.23$

why?

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

$7^{x}=77$

then, using placing logarith with base 7 on both sides of the equation, we have:

$7^{x}=77log_{7}(7^{x})=log_{7}(77)x=log_{7}(77)x=2.2322$

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

$x=2.23$

hence, we have that the correct option:

b. $x=2.23$

have a nice day!

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