Mathematics, 25.06.2019 09:30 Vishal123180

How do you determine whether you are finding a percent of increase or a percent of decrease between two values? explain.

Answers: 1

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Answer from: NetherisIsTheQueen

Increase:

It will have increase when y>x

so, percentage of increase is

$=\frac{y-x}{x}\times 100$

Decrease:

It will have decrease when x>y

so, percentage of decrease is

$=\frac{x-y}{x}\times 100$

Step-by-step explanation:

Let's assume initial value as x

assume final value as y

Increase:

It will have increase when y>x

so, percentage of increase is

$=\frac{y-x}{x}\times 100$

For example:

Initial value is 40

So, x=40

Final value is 50

so, y=50

now, we can find percentage in increase

$=\frac{50-40}{40}\times 100$

=25

Decrease:

It will have decrease when x>y

so, percentage of decrease is

$=\frac{x-y}{x}\times 100$

For example:

Initial value is 50

So, x=50

Final value is 40

so, y=40

now, we can find percentage in decrease

$=\frac{50-40}{40}\times 100$

=25

Answer from: Quest

Think of it as five or above give it a shove. change the 5 or above to the right to a zero and add one to the number on the left.
Can someone me with this! it’s for my little sister and she’s not sure what she has to do. asap

Can someone me with this! it’s for my little sister and she’s not sure what she has to do. asap

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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