What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6 ? enter your answer in the box.

y=\frac{1}{2}x-2

Step-by-step explanation:

we are given

Line is perpendicular to y=−2x−6

we can compare it with

y=mx+b

where

m is slope

so, m=-2

so, slope is -2

Our line is perpendicular to this slope

so, slope of our line will be

now, we are given point as (6,1)

so,

now, we can use point slope form of line

we can plug values

now, we can solve for y

and we get

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

4.

step-by-step explanation:

it have the same area.brainliest