Can someone me i need to know the solution to 2x+y=20 and -5y=-6x+12

2x+y=20 --> x=10-1/2y

-5y=6x+12v --> y=6/5x-12/5

Step-by-step explanation:

The first step is to turn them into a linear equation.

2x + y = 20

-2x        -2x

y = -2x +20

-5y = -6x + 12

-5       -5      -5

y = 6/5x - 12/5

The second step is to find the solution:

-2x + 20 = 6/5x - 12/5

+2x            +2x

20 = 16/5x - 12/5

+12/5         +12/5

112/5 = 16/5x

16/5      16/5

7 = x

The last step is to check to see if the solution works:

-2(7) + 20 = 6/5(7) - 12/5

-14 + 20 = 42/5 - 12/5

6 = 6

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.