35 points asap : ) find the solution to this system of equations. y = 6x - 6 2x + 2y = 2 give your answer as an ordered pair. find the solution to this system of equations. y = -3x + 5 5x - 4y = -3 give your answer as an ordered pair.

So with this system, I will be using the substitution method. Since we know that y = 6x - 6, substitute y in the second equation for 6x - 6 and solve for x as such:

Since we know the value of x is 1, substitute it into either equation to solve for y:

In the form of (x,y), the answer is (1,0).

For this system, I will also be using the substitution method. Since we know that y = -3x + 5, substitute that into the second equation to solve for x as such:

Since we know that the value of x is 1, substitute it into either equation to solve for y:

In (x,y) form, the answer is (1,2).

In short:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation:

b and c