If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7)

-13.

Step-by-step explanation:

If g(x) is linear function, then'\

Since g(-3) = 2 and g(1) = -4, then

Subtract from the first equation the second one:

Then

Hence, the equation of the linear function is

Then

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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