Acircular picture is 8 inches in diameter. part a what is the area of the picture in square inches? a. 4π square inches b. 8π square inches c. 16π square inches d. 32π square inches part b a frame that is 2 inches wide surrounds the picture. what is the total area of the picture and the frame in square inches? a. 4π square inches b. 12π square inches c. 36π square inches d. 40π square inches

Part A   C. 16π square inches

Part B  C. 36π square inches

Step-by-step explanation:

If we know the diameter, we can calculate the radius

d= 2r

8 = 2r

Divide by 2

8/2 =2r/2

4=r

The radius is 4 inches

Area of a circle is

A = pi *r^2

A = pi *4^2

A = 16 pi inches^2

Part B

If the frame is 2 inches wide, we add 2 to the radius

r = 4+2=6

A = pi r^2

A = pi *6^2

A = 36pi inches ^2

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol