How many ways can five dogs line up to be groomed ?

120 ways

Step-by-step explanation:

we have to find the numbers of ways for five dogs line up to be groomed.

For solving this , we should use method of permutation.

Number of permutation of n things taken r at time:

P(n,r)= n!/(n-r)!

From question statement, we observe that

n=5  and r=5 (since 5 dogs are taken at atime)

P(5,5)= 5!/(5-5)!

P(5,5)= 5!/0!                  ∵ 0!=1

P(5,5)= 5!/1

P(5,5)=5!

P(5,5)= 5×4×3×2×1

P(5,5)=120 ways.

hence, there are 120 ways for five dogs line up to be groomed.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

b

step-by-step explanation: