Find a fourth degree polynomial equation with integer coefficients that has the given numbers as roots. be sure to show all of your work. 2i, 4-i

Step-by-step explanation:

We are given that the roots of the polynomial are 2i and 4-i.

Since, the given roots are complex roots and we know that, 'Complex roots always occurs in pairs'.

So, we get that,

The roots of the given polynomial are 2i, -2i, 4-i and 4+i.

i.e.

i.e.

i.e.

i.e.

i.e.

i.e.

i.e.

Hence, the fourth degree polynomial having roots 2i, 4-i is .

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐