Hhhh i don't know how to do this- ; ; ; ; ;

Hello from MrBillDoesMath!

2, 10, 50, 250

Discussion:

a(n) = 2*(5)^(n-1)            n = 1,2,3..

So

a(1) = 2 * (5^0) = 2 * 1 = 2

a(2) = 2* (5)^(2-1) = 2 *5 = 10

a(3) = 2 * (5)^(3-1) = 2 * 5^2 = 2 * 25 = 50

a(4)  = 2 * (5)^(4-1) = 2 * 5^3  = 2 * 125 = 250

Thank you,

MrB

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point