Which of these sortition methods can be used to select a person for a certain task from among 24 candidates? a. throw 2 dice. assign a combination (for example 5-6) to each candidate. b. flip a coin 5 times. assign a sequence (for example h-t-h-h-t) to each candidate. c. roll a dice 1 time and flip a coin 2 times. assign a sequence (for example 4-h-t) to each candidate. d. flip a coin and roll 2 dice. assign a sequence (for example h-3-4) to each candidate.
C. Roll a dice 1 time and flip a coin 2 times. Assign a sequence (for example 4-H-T) to each candidate
All of these methods can be used. In methods A, B and D, there are more possible outcomes than candidates, so the process may need to be repeated—possibly several times—in order to choose a candidate.
For methods A and D, the dice need to be separately identifiable.
For option D, each candidate can have 3 different sequences assigned, as there are 72 possible outcomes (3 times 24). That way, one execution of the method will result in a chosen candidate.
Method C is the simplest, because there are exactly 24 outcomes
There are 24 candidates so we need an experiment that has 24 different outcomes. To find the total number of outcomes, you multiply the number of outcomes for each individual part of the trial.
A dice has 6 outcomes and each coin has 2.
6 x 2 x 2 = 24
With this candidate, you have 24 elements in the sample space which means that this method could be used
hope this helps