Infinitely many solutions.
First, make both equations equal to each other.
4x + 8 = 5x + 1
Subtract 4x from both sides.
8 = x + 1
Subtract 1 from both sides.
7 = x
When x > 0, there are infinitely many solutions.
When x = 0, there is only one solution.
When x < 0, there are no solutions.
In this case, x = 7, and 7 > 0. Therefore there are infinitely many solutions.
the answer to this question is yes