Mark is in a deep hole looking for treasure. he is standing 8 feet below the surface. he throws an old coin he found with an initial upward velocity of 22 ft/sec. how long until it lands outside the hole, having gone up and come back down? use the formula where h is the height of the coin in feet (relative to the surface) and t is the time in seconds since mark threw it. ignore air resistance and round your answer to the nearest tenth.
Option D is correct.
We have been given a function:
We will find at h=0 to find the time it will take until it lands outside the hole, having gone up and come back down.
In the given function we will put h=0.
On solving the above equation we will get t
So, it will never happen we are getting time as imaginary value.
Hence, it will not make it outside the hole.
Therefore, option D is correct.
i am currently in the exact same situation rn. algebra2/adv algebra is killing
option a, c,d are correct.
from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have
therefore, by rhs rule,δtzb ≅δszb
by cpctc, sz≅tz
also, from δctz and δasz,
by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz
also,from δasz and δzsb,
by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb
hence, option a, c,d are correct.