Afurniture manufacturer produces chairs and sofas. each chair requires 10 yards of fabric, and each sofa requires 20 yards of fabric. the manufacturer has 300 yards of fabric available. to fulfill orders, the number of sofas must be at least twice the number of chairs. let x be the number of chairs and y the number of sofas. which inequalities are described in the problem? check all of the boxes that apply
it's p=50x+80y so it's B
Option B is correct.
We are given that manufacturer earn profit on both items.
Profit earn on a chair = $ 50
Profit earn on a sofa = $ 80
Let x be the number of chairs and y be the number of sofas.
⇒ Profit on x chairs = 50x
⇒ Profit on y sofas = 80y
Total Profit = 50x + 80y
let Profit function denoted by P
⇒ P = 50x + 80y
Therefore, Option C is correct .i.e., P = 50x + 80y
y>2x & 10x+20y<300 are the Correct answers.
This is a system of equation problems. You need to write 2 equations with the variables and solve them.
The equations are:
10c + 20s = 300
s = 2c
We can solve with substitution.
10c + 20(2c) = 300
10c + 40c = 300
50c = 300
c = 6
If there are 6 chairs, then there must be 12 sofas.