(a) calculate the molarity of a solution that contains 0.0345 mol nh4cl in 400 ml of solution. (b) how many moles of hno3 are present in 35.0 ml of a 2.20 m solution of nitric acid? (c) how many milliliters of 1.50 m koh solution are needed to supply 0.125 mil of koh ?

Step-by-step explanation:

(A) We know that Molarity=

Since, moles solute= 0.0345 and litres solution =400mL=0.400l, thus

Molarity=

=

=

(B) Moles solute=Molarity×litres solution

=2.20×0.0350

=0.077 moles

(C) Using the formula,

Litres solution=

=

=0.0833L=83.33mL

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.