24 pointsss for anyone who answers the of a square garden is 36x^2 -60+25 find the perimeter if x=3

The perimeter is 52

Step-by-step explanation:

The area is 36x^2 -60x+25

We set this equal to 0 to find the length and width

A= 36x^2 -60x+25

We notice that this is a perfect square trinomial

(a^2 -2ab-b^2) = (a-b)^2

let a = 6x  and b=5

A=(6x-5) (6x-5)

The length and width are the same since is it a square  (we know it is a square so they have to be equal)

The perimeter of a square is

P =4s

P =4 (6x-5)

Distribute the 4

  = 24x -20

Let x =3

P = 24(3) -20

  =72 -20

 = 52

The perimeter is 52

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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