F(x) = 0.2^x is transformed 9 units right, compressed vertically by a factor of 1/6 and reflected across the x-axis. write the transformed function g(x)

g(x) = -⅙(0.2)^(x – 9)

Step-by-step explanation:

F(x) = 0.2^x

(a) Transformation to the right

You transform a function 9 units to the right by subtracting 9 from the value of x. Thus, the function becomes

F₁(x) = 0.2^(x – 9)

(b) Vertical compression

To compress a function vertically by a factor of 6, you divide the whole function by 6. Thus, the function becomes

F₂(x) = ⅙F₁(x) =  ⅙(0.2)^(x – 9)

(c) Reflection across x-axis

When you reflect a point (x, y) across the x-axis, the x-coordinate remains the same, but the y-coordinate gets the opposite sign. Thus,

g(x) =  -⅙(0.2)^(x – 9)

The image below shows F(x) and its appearance after each of the operations.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2