Picture attached below. if you cannot read the numbers let me know. : )

14. the shortest side across from 30 degrees is 7 and the hypotenuse is always twice the length of the shortest side so y=14 and the middle length which is across from 60 degrees is always half the hypotenuse and root 3 so x= 7

16. The two sides (x and y) are congruent because it is an isos triangle so the sides would be half of the hypotenuse and root 2 so x&y=

18. This problem has both triangles in them so by using the same technique, just pretend the triangles are two separate triangles. So since it already has a root 2 in it then x= 24 and half of 24 is 12 so y= 12

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

the correct answers are 1, 2, 4, and 5! i just got it right!