Aparticle moves on x-axis blah its initial position is x(0)=27 and velocity is v(t)=4t^3-30t^2+72t-54 on the time interval 0
a) write an expression for the position function (general)
t^4-10t^3+36t^2-54t+c
b) when does the particle change direction?

c) find t when particle is moving to the right

d) find velocity when acceleration is 0.
ez, don't need for this one.

b) The particle changes direction when its velocity changes sign. Use the first derivative test to find the critical points:

Then for , we have ; for , we have ; and for , we have again. These three facts indicate that the velocity only changes once at .

c) Pick "to the right" to be the positive direction. Then you need to find where . We already did that above and found for .

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer