Ametal bar weighs 8.15 ounces. 93% of the bar is silver. how many ounces of silver are in the bar? (round to the nearest thousandth)

7.560 ounces

Step-by-step explanation:

Given : The weight of a metal bar = 8.15 ounces

Also, it is given that : 93% of the bar is silver.

We can write 93% as 0.93  [To convert percent into decimal or fraction , we divide it by 100.]

Now, the amount of silver in the metal bar = 93% of 5.15 ounces

Replace 'of' by '×' and '93%' by '0.93' , we get

The amount of silver in the metal bar =

Hence, there are 7.560 ounces of silver in the metal bar.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: