Acash box contained $12.25 in quarters, dimes, and nickel. if there were five more than twice as many dimes as nickels and one less than three times as many quarters as nickels. how many of each kind of coin was there. explain ur answer

Step-by-step explanation:

Let n represent the number of nickels. Then the number of dimes is ...

  dimes = 5 + 2n

and the number of quarters is ...

  quarters = -1 + 3n

So, the total value of the cash in the box is ...

  0.05n + 0.10(5 +2n) + 0.25(-1 +3n) = 12.25

  1.00n + 0.25 = 12.25

  n = (12.25 -0.25)/1.00 = 12

  dimes = 5+2·12 = 29

  quarters = -1 +3·12 = 35

There are 12 nickels, 29 dimes, and 35 quarters.

Check

.05·12 +.10·29 +.25·35 = 0.60 +2.90 +8.75 = 12.25 . . . . answer checks OK

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8