Find the perimeter of a square whose diagonal is 8 feet. round to the nearest tenth if needed.
math test tomorrow

Hello from MrBillDoesMath!

22.6

Discussion:

From the attachment, the square has sides of length "x", and the Pythagorean theorem applies. Hence

x^2 + x^2 = 8^2           =>

2 x^2 = 8^2                 => divide both sides by 4

x^2   = 8^2/2               => 8^2 = 64,   8^2/2 = 32

x^2 = 32                      =>

x = sqrt(32) =               => as 32 = 16 * 2

x = sqrt(16) *  sqrt(2)    =>

x = 4 sqrt(2)

The perimeter is 4*x

             = 4*(4 sqrt(2) )

             = 16 * sqrt(2)        => as sqrt(2) is approx 1.41

            = 22.6

Thank you,

MrB

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,