The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y-1 (x-12) what is the standa the equation for this line?

Step-by-step explanation:

(-2,2)(5,1)

slope(m) = (1 - 2) / (5 - (-2) = -1 / 7

y = mx + b

slope(m) = -1/7

use either of ur points(5,1)x = 5 and y = 1

now sub and find b, the y int

1 = -1/7(5) + b

1 = -5/7 + b

1 + 5/7 = b

7/7 + 5/7 = b

12/7 = b

equation is : y = -1/7x + 12/7but we need it in standard form...

y = -1/7x + 12/7

1/7x + y = 12/7

x + 7y = 12 <== standard form

bull

step-by-step explanation: