Which of the following functions is graphed below

The answer is A ⇒ y = Ix + 3I - 4

Step-by-step explanation:

∵ The equation with positive slope is:

∵ The line passing through (1 , 0) and (0 , -1)

∴ the slope = (-1 - 0)/(0 - 1) = -1/-1 = 1

∵ y- intercept = -1

∴ y = x - 1 ⇒ (1)

∵ The equation with negative slope is:

∵ The line passing through (-7 , 0) and (-3 , -4)

∴ the slope = (-4 - 0)/(-3 - -7) = -4/4 = -1

∴ y = -x + c ⇒ use point (-7 , 0) to find c

∴ 0 = -(-7) + c ⇒ 0 = 7 + c ⇒ c = -7

∴ y = -x - 7 ⇒ (2)

We will choose the answer which give us these equations

∵ A) ⇒ y = Ix + 3I - 4 ⇒ Ix + 3I means (x + 3) or -(x + 3)  

∴ y = x + 3 - 4 and y = -(x + 3) - 4

∴ y = x -1 and y = -x - 3 - 4 = -x - 7

∵ y = x - 1 is the same with equation (1)

∵ y = -x - 7 is the same with equation (2)

∴The answer is y = Ix + 3I - 4

this is a good question! i'll do some research and come back when i have the answer!