If 5 years ago nina was twice as old as sam, how soon from now will she be 1.5 times as old as sam? if x is sam's age 5 years ago, give your answer in terms of x.

In x - 5 years.

Step-by-step explanation:

5 years ago:

Sam's age: x

Nina's age: 2x

Now:

Sam's age: x + 5

Nina's age: 2x + 5

Let t be the number of years from now that Nina will be 1.5 times Sam's age.

In t years:

Sam's age: x + t + 5

Nina's age: 2x + t + 5

Nina will be 1.5 times Sam's age:

2x + t + 5 = 1.5(x + t + 5)

2x + t + 5 = (3/2)(x + t + 5)

2(2x + t + 5) = 3(x + t + 5)

4x + 2t + 10 = 3x + 3t + 15

4x + 10 = 3x + t + 15

x - 5 = t

t = x - 5

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)