What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in

a. 150 in squared

b. 197 in squared

c. 127 in squared

d. 210 in squared

ANSWER

EXPLANATION

The area of the two tra-pezoidal faces

The area of the 5 by 6.4 rectangular face

The area of the two square faces

The area of the 9 by 5 rectangular face is

The surface area of the design is:

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15