What is the 6th term in the sequence described by the following recursive formula?

a1=9
an=an−1−4

a) a6=−7
b) a6=−15
c) a6=−8
d) a6=−11

Correct answer is: D) a₆ = - 11

Step-by-step explanation:

Given:

a₁ = 9 and aₙ = aₙ₋₁ - 4

We know it is

a₆ = a₅ + d also it is given a₆ = a₅ - 4

When we equate the right sides of equality we get:

a₅ + d = a₅ - 4 => d = - 4

We also know it is   a₆ = a₁ + 5 d

Now we will find a₆

a₆ = 9 + 5 (-4) = 9 - 20 = - 11

a₆ = - 11

God with you!!!

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15