Answer, really need , will be very grateful to anyone who

a) a^2+ 2ab+ b^2=25, find a+b

b) a^2− 8ab+ 16b^2=81, find a–4b

a) ±5

b) ±9

Step-by-step explanation:

In each case, the expression on the left is the square of the expression you're asked to find the value of. Then the value of your expression is the square root of the constant on the right. That square root can be either positive or negative.

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a) a^2 +2ab +b^2 = (a +b)^2 = 25

(a +b) = ±√25 = ±5

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b) a^2 -8ab +16b^2 = (a -4b)^2 = 81

(a -4b) = ±√81 = ±9

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i