What is the value of y? 3y^2 − 6 = 42

Hey there!

Let's start by adding 6 to both sides of the equation to eliminate the -6.

3y^2 = 48

Next, let's divide both sides by 3 to eliminate the 3.

y^2 = 16

Find the square root of both sides.

y = ±4

It can be both positive or negative 4 because -4 x -4 and 4 x 4 both equal 16.

The value of y is ±4.

Hope this helps!