The perimeter of a playing field for a certain sport is 320 ft. the field is a? rectangle, and the length is 48 ft longer than the width. find the dimensions.

length: 104 ftwidth: 56 ft

Step-by-step explanation:

Let L and W represent the length and width of the field. Then the perimeter is given by ...

  P = 2(L +W)

Filling in the given information, we have ...

  320 = 2(L +W)

  L = W +48 . . . . . . the length is 48 ft longer than the width

Using the second equation in the first, we get

  320 = 2((W +48) +W)

  320 = 4W +96 . . . . . . simplify

  224 = 4W . . . . . . . . . . subtract 96

  56 = W . . . . . . . . . . . . .divide by 4

  L = 56 +48 = 104 . . . . find L using the above relation

The width of the field is 56 ft; the length is 104 ft.

A5 miles because when you look at the chart count how many times it goes into it i don’t even know wha,t i’m saying anymore mpbut long stor6 short it’s 5 miles

Okay so for every triangle has three angles that always add up to 180 degrees. and to tell the difference between whether they are secure, right or obtuse is that acute: has one angle that is less than 90 degrees. right triangle means there is at least one angle that is exactly 90 degrees. and an obtuse angle has an angle that is bigger than 180 degrees. i’ll do #13 as an example: 13. 40 and 50 so if every triangle has 180 degrees 40+50= 90 degrees then180-90= 90 degrees so the third angle is 90 degrees and because this triangle has a 90 degree angle it means it is a right triangle