Aset of data has a high-value outliner. how do you expect the standard deviation to change when the outliner is removed? would the result be different if the data had a low-value outliner instead? explain

The standard deviation should reduce in value.

It doesn't matter whether it is high or low value

Step-by-step explanation:

Removing outliers makes the data less spread out, which will reduce the value of the variance and standard deviation.  It doesn't matter if the outlier is a high-value or a low-value outlier.

the answer would be c:   ax + b = ax + c

step-by-step explanation:

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m