Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1?
f(x) = (x – 2i)(x – 3i)
f(x) = (x + 2i)(x + 3i)
f(x) = (x – 2)(x – 3)(x – 2i)(x – 3i)
f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)

f(x) = (x – 2i)(x – 3i)

Step-by-step explanation:

The above funtion gives us roots

x - 2i = 0 , x - 3i = 0

x = 2i , x = 3i

Both the roots have multiplicity 1.

And for leading coefficient, there will be only one variable having power 2 which is x^2 and the coefficient is 1 so the first function fulfills all conditions.

answer:

step-by-step explanation: