If p is a point of symmetry, click on the graphic to find the figure that is symmetrical by p.

The third figure is the answer (Look to the attached figure

Step-by-step explanation:

* The point of symmetry means

- If a figure or graph can be rotated 180° about a point P

 and end up looking identical to the original, then P is a point

 of symmetry

- The same distance from the central point

  but in the opposite direction.

* Lets look to the four answers

- In the 3rd figure first line up can be rotated 180° about a point P

 and end up looking identical to the second line down, then P

 is a point of symmetry

- The same distance from the point  p

  but in the opposite direction.

* The figure show the answer

Figure 3rd is correct.

Step-by-step explanation:

Given: Point P is a point of symmetry.

To find: Symmetrical figure.

Point P is a point of symmetry means Figure is symmetrical about point P.

Point P is on x-axis so, Figure must be symmetrical about x-axis.

Figure 1: It is not symmetrical About Point P. It is symmetrical about line y = x.

Figure 2: It is not symmetrical About Point P as it is symmetrical about y-axis.

Figure 3: It is symmetrical About Point P.

Figure 4: It is not symmetrical About Point P.

Therefore, Figure 3rd is correct.

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.