Rewrite the function y = x2 0 6x + 14 in vertex form, y = (x 0 h)2 + k.

a) y = (x 0 3)2 + 5
b) y = (x + 5)2 + 3
c) y = (x + 3)2 0 5
d) y = (x 0 5)2 0 3

If I rewrite the funciton y=x^2 - 6x + 14 in vertex for, y = (x - h)^2 + k, then the answer would be a) y= (x-3)^2 + 5. I chose letter a because all the others do not coincide to the vertex form of the given quadratic equation. Thus, letter a is the answer. 

(6,0) i hope it makes enough sense