Dylan, alan, bruce, and cecil are brothers. dylan weighs d pounds. alan weighs 3 pounds more than twice what dylan weighs. bruce weighs 12 pounds less than three times what dylan weighs. if cecil weighs the same as the combined weight of bruce and alan, what is cecil’s weight in terms of dylan’s weight (d)?

complete the steps below to solve this problem and others like it.

part a

alan weighs 3 pounds more than twice what dylan weighs. write an expression to represent alan’s weight in terms of dylan’s weight.

Part A: 2D + 3 = A

Note: I have likely given you the answer to the whole problem. See below.

Step-by-step explanation:

Givens

Comment

You have to pay the most attention to Alan and Bruce. Once you have equations for those two. Cecil's weight is just the sum of those two.

Alan

Alan = Twice*Dylan + 3 or

A = 2*D + 3

Bruce

Bruce = three * Dylan - 12

B = 3*D - 12

Cecil

Cecil = Alan + Bruce

C = A + B

Note

The last equation shows you how to combine the first two.

C = A + B

A = 2D + 3

B = 3D - 12

C = 2D + 3 + 3D - 12

C = 5D - 9

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

l.ln.lln.k.nkl

step-by-step explanation: