The figure below shows a triangle with vertices a and b on a circle and vertex c outside it. side ac is tangent to the circle. side bc is a secant intersecting the circle at point x:

the figure shows a circle with points a and b on it and point c outside it. side bc of triangle abc intersects the circle at po

what is the measure of angle acb? (6 points)

23°

32°

46°

16°

The correct option is C. 46°

Step-by-step explanation:

First find the measure of the arc AX

Now, Arc measure is twice the angle formed in the segment by the same arc

⇒ Measure AX = 2 × ∠ABX

⇒ Measure AX = 2 × 32°

⇒ Measure AX = 64°

Now we will use tangent-secant angle formula to find the measure of ∠ACB as ∠ACB is formed by tangent AC and secant BC outside our given circle.

⇒ ∠ACB = 0.5 × (Measure of major arc - Measure of minor arc)

⇒ ∠ACB = 0.5 × (156° - 64°)

⇒ ∠ACB = 0.5 × 92°

⇒ ACB = 46°

Therefore, The correct option is C. 46°

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: