Suppose the depth of the tide in a certain harbor can be modeled by y = 20 + 5 cos (pi/6 t), where y is the water depth in feet and t is the time in hours. consider a day in which t = 0 represents 12: 00 midnight. for that day, when are high tide and low tide and what is the depth of each?

The tide in the harbor is represented by the equation

y = 20 + 5*cos (π/6 * t)

where y is the water depth in feet and t is the time in hours.

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph .

t = 0 represents 12:00 midnight

If we take a look at the graph, we can see that the low tide occurs at

t = 6.   This means at 6 am (six hours later from midnight)

At this time, the depth is equal to 15 feet.

The high tide occurs at mid-day

t = 12 (twelve hours from midnight)

At this time, the depth is equal to 25 feet.

Low tide

(6 hours, 15 ft)

High tide

(12 hours, 25 ft)

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

no idea

step-by-step explanation: