30 points. precalculus .
find the limit of the function algebraically.
use the given graph to determine the limit, if it exists.

1.

lim x→ 0+ f(x)

you will find the limit is inf

lim x→ 0- f(x)

you will find the limit is - inf

because

lim x→0+ f(x) no equal to lim x→0- f(x)

thus lim x→0 f(x) does not exist

2.

form the graph

lim x→2- f(x) = 6

lim x→2+ f(x)= -2

because

lim x→2- f(x) not equal tolim x→2+ f(x)

thus lim x→2 f(x) does not exist

hope this would help you.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)