Consider a game in which a player rolls a number cube to determine the number of points earned. if a player rolls a number greater than or equal to 4, the number of the roll is added to the total points. any other roll is deducted from the player's total. what is the expected value of the points earned on a single roll in this game?

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Step-by-step explanation:

The expected value would be a gain of 1,5

Step-by-step explanation:

For any calculation of expecte value you should multiply the probability of every chance with his value or gain, for example, for this dice

If your roll 1

p(1) = 1/6, and his gain is -1

If your roll 2

p(2) = 1/6, and his gain is -2

If your roll 3

p(3) = 1/6, and his gain is -3

If your roll 4

p(4) = 1/6, and his gain is 4

If your roll 5

p(5) = 1/6, and his gain is 5

If your roll 6

p(6) = 1/6, and his gain is 6

So the expecte value would be

E = p(1)*(-1) + p(2)*(-2)+p(3)*(-3)+p(4)*(4)+p(5)*5+p(6)*6

p(1)=p(2)=p(3)=p(4)=p(5)=p(6)=1/6 because this dice is a cube, with even chances to fall in any face.

E = (1/6)*(-1-2-3+4+5+6)

E=(1/6)*(-6+15)

E=(1/6)*(9)

E=1,5

The expected value would be a gain of 1,5

answer: a.   one is a factor of every whole number since every number is divisible by itself.

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step-by-step explanation

2r= 2300

r =1150