Evaluate the surface integraliintegral. gifsf � dsfor the given vector field f and the oriented surface s. in other words, find the flux of f across s. for closed surfaces, use the positive (outward) orientation. f(x, y, z) = xy i + yz j + zx ks is the part of the paraboloidz = 2 ? x2 ? y2 that lies above the square 0 ? x ? 1, 0 ? y ? 1,and has upward orientation

Looks like the paraboloid has equation

and is the part of this surface with and . Parameterize by

with and . Take the normal vector to to be

Then the flux of across is

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

to have more of what you want like money

step-by-step explanation:

save it by not spending on unnecessary stuff and have more