Which function has a period equal to half the period of the function in y = -3sin(2/3x - 2π) + 2?
a. y = 3cos(2/3x - π) + 2
b. y = -3/2cos(2/3x - 2π) + 2
c. y = -3cos(2/3x - 2π) + 2
d. y = 3cos(4/3x - 2π) + 2

D.

Step-by-step explanation:

The given function is:

This function is of the form:

, where

The period is given by:

Half of this period is .

The function that has a period of is

first one because it can't have a fraction in it

step-by-step explanation: