Find the length and width
a= 20 cm2
p= 18cm

The length is 5 cm and the width is 4 cm

Step-by-step explanation:

I assume that is a rectangle

Let

x----> the length of rectangle

y ---> the width of rectangle

we know that

The area of rectangle is

A=xy

A=20 cm²

so

20=xy -----> equation A

The perimeter of rectangle is

P=2(x+y)

P=18 cm

so

18=2(x+y)

9=x+y -----> y=9-x ----> equation B

Substitute equation B in equation A and solve for x

20=x(9-x)

20=9x-x²

x²-9x+20=0

Solve the quadratic equation by graphing

The solution is x=5 cm (I assume that the length is greater than the width)

see the attached figure

Find the value of y

y=9-5=4 cm

therefore

The length is 5 cm

The width is 4 cm

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column