Graph the function f(x) = 2 √ x +3

Find the domain for  

y

=

√

x

−

3

+

2

y=x-3+2

so that a list of  

x

x

values can be picked to find a list of points, which will help graphing the radical.

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[

3

,

∞

)

[3,∞)

{

x

|

x

≥

3

}

{x|x≥3}

To find the radical expression end point, substitute the  

x

x

value  

3

3

, which is the least value in the domain, into  

f

(

x

)

=

√

x

−

3

+

2

f(x)=x-3+2

.

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2

2

The radical expression end point is  

(

3

,

2

)

(3,2)

.

(

3

,

2

)

(3,2)

Select few  

x

x

values from the domain. It would be more useful to select the values so that they are next to the  

x

x

value of the radical expression end point.

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x

y

3

2

4

3

5

3.41

xy324353.41

Step-by-step explanation:

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.